Chemical
Bonding

H2 Chemistry (9476), JC1

By the end of this topic, you can answer

1

Why does a copper wire bend when you hammer it, while a salt crystal shatters?

2

Why does salt conduct electricity when molten or dissolved, but not as a solid?

3

Oxygen forms only two bonds with fluorine, so how can sulfur form six in SF6?

4

Why is a water molecule bent while carbon dioxide is straight, and why does that make only water polar?

5

Why is a C=C bond stronger than a C–C bond, but not twice as strong?

6

Water (Mr 18) boils at 100 °C, but the heavier H2S (Mr 34) boils at −60 °C. Why?

7

Diamond and graphite are both pure carbon. Why is one the hardest natural substance and the other soft enough to write with?

Recall: what you know from O levels

1Name the type of bonding in NaCl, H₂O and Cu.

NaCl ionic, H₂O covalent, Cu metallic.[1]

2Why does NaCl have a high melting point?

Its giant lattice has strong attractions between oppositely charged ions, needing a lot of energy to overcome.[1]

3Why does water boil at a much lower temperature than NaCl melts?

Boiling water only overcomes the weak forces between molecules, not the covalent bonds within them.[1]
1

Types of Chemical Bonds

All bonds and intermolecular forces are electrostatic attractions between …

Strong bonds
metallicpositive metal cations and a sea of delocalised valence electrons
ionicoppositely charged cations and anions
covalentthe nuclei of each atom and the shared pair(s) of electrons
Weak intermolecular forces (IMFs)
id–idnon-polar molecules
pd–pdpolar molecules
H bondthe protonic H of one molecule and a lone pair on F, O or N of another
2

Metallic Bonding

2.1Structure and bonding

Metals have a giant metallic lattice structure, with strong electrostatic forces of attraction between a sea of delocalised valence electrons and a lattice of positive metal cations.

AnalogyEach metal atom gives its valence electrons to a shared pool. The positive cations are held together by the "glue" of the electrons moving among them.

2

Metallic Bonding

2.2Factors affecting strength

Strength of metallic bond ↑ when

  1. Charge of cation ↑ and ionic radius ↓ → charge density of cation ↑
  2. No. of valence e⁻ ↑ → more delocalised e⁻ in the sea
  3. → stronger attraction → more energy required to overcome it → m.p. ↑
2

Metallic Bonding

Worked exampleExplain why the melting point of aluminium (660 °C) is higher than that of sodium (98 °C).

  1. Both Al and Na have a giant metallic lattice structure
  2. Al delocalises 3 valence e⁻ per atom, Na only 1. Al³⁺ has a higher charge and smaller ionic radius than Na⁺
  3. → more energy is needed to overcome the stronger electrostatic forces of attraction between Al³⁺ cations and the sea of delocalised e⁻ than between Na⁺ cations and its sea of delocalised e⁻

Your turnExplain why the melting point of potassium (63 °C) is lower than that of sodium (98 °C).

Both have a giant metallic lattice structure. Both K⁺ and Na⁺ have a charge of +1 and each atom contributes one electron to the sea of delocalised electrons, but K⁺ has a larger ionic radius, so K⁺ has a lower charge density.[1]
Hence, less energy is needed to overcome the weaker electrostatic attraction between the K⁺ cations and the sea of delocalised electrons.[1]
2

Metallic Bonding

2.3Physical properties

  • Conduct electricity in all states: delocalised valence e⁻ become mobile and migrate freely when a potential difference is applied. More delocalised e⁻ → higher conductivity.
  • Good thermal conductors: delocalised e⁻ throughout the structure transfer kinetic energy quickly from one end to the other.
  • Malleable and ductile: metallic bonds are non-directional, so layers of cations slide over one another without overcoming the attraction between cations and the sea of e⁻.
3

Ionic Bonding

3.1Structure and bonding

Ionic compounds have a giant ionic lattice structure with strong electrostatic forces of attraction between cations and anions.

DefinitionCoordination number: the number of oppositely charged ions surrounding an ion in a crystal lattice.

NaClIn this layer, 4 Cl⁻ surround each Na⁺, one more sits above and one below, so the coordination number is 6 for both Na⁺ and Cl⁻.
3

Ionic Bonding

Dot-and-cross diagram of MgO

  • Mg loses its 2 valence e⁻ (crosses), O gains them.
  • Show valence e⁻ only, as dots and crosses
  • Square brackets with the charge outside
  • No. of each ion as a coefficient, e.g. Ca²⁺ 2[F]⁻
3

Ionic Bonding

3.2Factors affecting strength

lattice energy ∝ q₊ × q₋r₊ + r₋

Greater charge and smaller ionic radii → greater magnitude of lattice energy → more energy required to overcome the attraction.

AnalogyTwo magnets: stronger magnets, held closer together, are harder to pull apart.

3

Ionic Bonding

Worked exampleExplain why the melting point of MgO (2852 °C) is higher than that of Na₂O (1132 °C).

  1. Both have a giant ionic lattice structure
  2. Mg²⁺ has a higher charge and smaller ionic radius than Na⁺ → greater magnitude of lattice energy
  3. → more energy is needed to overcome the stronger electrostatic forces of attraction between Mg²⁺ and O²⁻ ions than between Na⁺ and O²⁻ ions

Your turnExplain why NaF (993 °C) has a higher melting point than NaCl (801 °C).

Both have a giant ionic lattice structure. F⁻ has a smaller ionic radius than Cl⁻ and the same charge, so the magnitude of the lattice energy of NaF is greater than that of NaCl.[1]
Hence, more energy is needed to overcome the stronger electrostatic attraction between Na⁺ and F⁻ ions than between Na⁺ and Cl⁻ ions.[1]
3

Ionic Bonding

3.3Physical properties

  • Conducts when molten or aqueous: ions are mobile and migrate to the electrodes when a p.d. is applied. In the solid, ions are held in fixed positions.
  • Hard: a large amount of energy is needed to overcome the strong attraction. Brittle: under force, layers slide, ions of like charges come together and repel → the lattice shatters.
  • Soluble in polar solvents: energy released forming ion–dipole interactions compensates for overcoming the ionic attraction and the solvent–solvent forces. Insoluble in non-polar solvents.
3

Ionic Bonding

3.4Ionic bonds with covalent character

  • A small, highly charged cation polarises (distorts) the electron cloud of the anion → electron density drawn between the nuclei → partial sharing of e⁻ → covalent character
  • Polarising power of cation ↑ with charge density ∝ q₊ / r₊
  • Polarisability of anion ↑ with anion size
3

Ionic Bonding

Worked exampleAre Al₂O₃ and AlBr₃ largely ionic or covalent? Compare with AlCl₃.

  1. Al³⁺ has a high charge density → high polarising power
  2. O²⁻ is smaller and less polarisable than Cl⁻ → electron density unshared with Al³⁺ → Al₂O₃ largely ionic
  3. Br⁻ is larger and more polarisable than Cl⁻ → electron density largely shared → AlBr₃ largely covalent
3

Ionic Bonding

Quick checkWhich compound has the highest melting point?

ANaCl
BMgO
CKCl
DNaBr
NoteB: Mg²⁺ and O²⁻ both carry charge 2 and are small, so the lattice energy is by far the largest in magnitude. The others are all +1/−1.
4

Covalent Bonding

DefinitionCovalent bond: the strong electrostatic forces of attraction between the nuclei of each atom and the shared pair(s) of electrons.

Definitionσ bond: a covalent bond formed by head-on overlap of orbitals. Electron density is concentrated between the nuclei.

Definitionπ bond: a covalent bond formed by sideways overlap of p orbitals, giving two regions of overlap above and below the inter-nuclear axis.

4

Covalent Bonding

Why is a π bond weaker than a σ bond?

  1. π overlap lies above and below the inter-nuclear axis → less effective overlap → π bond weaker than σ
  2. A π bond only forms after a σ bond: the σ overlap brings the atoms close enough for the p orbitals to overlap sideways
Bondσπ
single10
double11
triple12
4

Covalent Bonding

4.1Co-ordinate (dative) bonds

DefinitionDative bond: a covalent bond formed when an atom donates a lone pair of electrons into an empty orbital of an electron-deficient atom for sharing.
  • Shown as an arrow from donor to acceptor, or as 2 e⁻ of the same type in a dot-and-cross diagram. Once formed, it is identical to a normal covalent bond.
  • Lewis acid: electron pair acceptor. Lewis base: electron pair donor. E.g. BF₃ (acid) + NH₃ (base) → H₃N→BF₃
  • Al₂Cl₆: each Al accepts a lone pair from a Cl of the other AlCl₃, so each Al gets an octet.
4

Covalent Bonding

Quick checkHow many σ and π bonds are in one molecule of ethene, CH₂=CH₂?

A4 σ, 2 π
B5 σ, 1 π
C6 σ, 0 π
D4 σ, 1 π
NoteB: 4 C–H single bonds (4 σ) and one C=C double bond (1 σ + 1 π).
4

Covalent Bonding

4.2Drawing steps: CO₂

  1. Central atom: forms the most bonds, or is the least electronegative (not H)
  2. Anion: add e⁻ to the more electronegative atom(s). Cation: remove e⁻ from the less electronegative atom(s). Square brackets, charge outside
  3. Give each atom an octet with single, double or triple bonds
  4. Period 2 atoms: maximum 8 valence e⁻
4

Covalent Bonding

4.2Exceptions to the octet rule

TypeExamples (e⁻ around central atom)
Expanded octetPCl₅ (10), SF₆ (12), XeF₄ (12)
Electron-deficientBeCl₂ (4), BF₃ (6), AlCl₃ (6)
Odd no. of e⁻ (radicals)NO, NO₂, ClO₂ (11, 17, 19 valence e⁻ in all)

Period 3 and higher atoms have vacant, energetically accessible d orbitals to expand the octet. Period 2 atoms cannot, so NCl₅ does not exist.

4

Covalent Bonding

4.2Examples  × and • are electrons from different atoms

N₂a triple bond
CO₂two double bonds
C₂H₄a C=C double bond
NH₃one lone pair on N
BF₃only 6 e⁻ around B
NH₄⁺dative pair from N
4

Covalent Bonding

Your turnDraw the dot-and-cross diagrams of (a) H₂O and (b) N₂. Show outer electrons only.

NoteO is central with 2 lone pairs, N₂ needs a triple bond so each N has an octet.
4

Covalent Bonding

4.3Electronegativity: covalent bonds with ionic character

DefinitionElectronegativity: the measure of an atom's ability to attract electrons in a bond.
  • Across a period ↑: nuclear charge ↑, shielding about constant → bonding e⁻ more strongly attracted
  • Down a group ↓: more shells → bonding e⁻ further away and more shielded
  • Different electronegativities → bonding e⁻ drawn to the more electronegative atom → permanent dipole: a polar bond
4

Covalent Bonding

  1. Electron pairs around the central atom are arranged as far apart as possible to minimise repulsion
  2. Repulsion: lone pair–lone pair > lone pair–bond pair > bond pair–bond pair
  • A lone pair repels more strongly: it is non-bonding, so its electron density is closer to the nucleus
  • A double or triple bond counts as one region of electron density

AnalogyRival campers on a tiny round planet pitch their tents as far apart as they can: two end up at opposite poles, three spread round the equator, four sit at the corners of a tetrahedron.

4

Covalent Bonding

4

Covalent Bonding

Each basic shape (dotted) gives the other shapes: replace bond pairs by lone pairs one at a time. The electron pairs keep the basic arrangement, but the shape is named from the positions of the atoms only.

4

Covalent Bonding

AnalogyA lone pair is a camper with a bigger tent: it takes up more room close to the centre and pushes the other tents closer together.

Answer structureShape, e.g. NH₃
  1. There are 3 bond pairs and 1 lone pair around N
  2. To minimise repulsion, the 4 electron pairs are arranged as far apart as possible
  3. → NH₃ is trigonal pyramidal, bond angle 107°
4

Covalent Bonding

Electronegativity and bond angle

  1. NF₃ 102° < NH₃ 107°: F more electronegative → bonding e⁻ closer to F → less crowding around N → less repulsion → smaller angle
  2. H₂O 104.5° > H₂S 92°: O more electronegative → bonding e⁻ drawn towards O → more crowding → more repulsion → larger angle

Your turnState the shape and bond angle of (a) PCl₃, (b) SF₆, (c) XeF₄.

(a)
PCl₃: 3 bond pairs and 1 lone pair: trigonal pyramidal, about 107°[1]
(b)
SF₆: 6 bond pairs and no lone pairs: octahedral, 90°[1]
(c)
XeF₄: 4 bond pairs and 2 lone pairs, with the lone pairs opposite each other: square planar, 90°[1]
4

Covalent Bonding

4.5Finding the shape of an ion or an unfamiliar molecule

Take the central atom's valence electrons, add one for each atom bonded to it, add 1 for each negative charge or subtract 1 for each positive charge, then divide by 2.

ionpairsbond and lone pairsshape
PH₄⁺(5 + 4 − 1)/2 = 44 bp, 0 lptetrahedral
ICl₄⁻(7 + 4 + 1)/2 = 64 bp, 2 lpsquare planar
  • Try =O first (CO₂, SO₂). In an oxoanion, the charge gives the number of –O⁻ (CO₃²⁻, SO₄²⁻). Use →O when the central atom cannot take =O (NO₂).
  • Swap an unfamiliar atom for one with the same covalency (number of bonds): CHCl₃ as CH₄, F₂O as H₂O, BH₄⁻ as CH₄, CH₃⁺ as BCl₃.
4

Covalent Bonding

  1. Identify any polar bonds (bond dipoles)
  2. Determine the shape of the molecule
  3. Resolve the dipoles: net dipole → polar
Answer structureX is a polar / non-polar molecule as the dipoles do not cancel / cancel each other out. Hence there is / isn't an overall dipole moment.

AnalogyA tug of war: two equal teams pulling in opposite directions go nowhere (CO₂). Pull at an angle and the rope moves (H₂O).

4

Covalent Bonding

Quick checkWhich molecule is polar?

ACCl₄
BBF₃
CCO₂
DCHCl₃
NoteD: in CHCl₃ one C–H bond replaces a C–Cl, so the tetrahedral dipoles no longer cancel. CCl₄, BF₃ and CO₂ are symmetrical, so their dipoles cancel.
4

Covalent Bonding

4.7Bond energy and bond length

DefinitionBond dissociation energy: the enthalpy change when one mole of a particular covalent bond between atoms in a gaseous molecule is broken.  Cl₂(g) → 2Cl(g)  +244 kJ mol⁻¹

DefinitionBond length: the distance between the nuclei of the atoms in a covalent bond. Shorter bond = stronger bond.

  1. Orbital overlap: larger bonding atoms → larger, more diffused valence orbitals → less effective overlap → weaker bond
  2. Polarity: may ↑ or ↓ strength (deduce from data), e.g. N–H 390 < O–H 460 < F–H 562
  3. Multiplicity: triple > double > single. BE(C=C) < 2 × BE(C–C) as the π bond is weaker than σ
5

Intermolecular Forces

5.1Instantaneous dipole–induced dipole (id–id)

Definitionid–id: weak electrostatic forces of attraction between non-polar molecules (present between all molecules).
  1. Continuous movement of e⁻ → at an instant, one region has slightly higher electron density
  2. This instantaneous dipole induces a dipole in a nearby molecule
  3. The two molecules attract by weak electrostatic forces between opposite partial charges
5

Intermolecular Forces

What makes id–id stronger?

  • No. of electrons ↑ (larger Mr) → electron cloud more polarisable → stronger id–id. F₂ −188 °C, Cl₂ −34 °C, Br₂ 59 °C
  • Surface area ↑ → more extensive id–id. pentane 36 °C > 2,2-dimethylpropane 10 °C

AnalogyTwo strips of tape stick along their whole length, two balls touch at one point only.

5

Intermolecular Forces

5.2Permanent dipole–permanent dipole (pd–pd)

Definitionpd–pd: weak electrostatic forces of attraction between polar molecules, in addition to id–id.

The larger the magnitude of the overall dipole moment, the stronger the pd–pd interactions.

CompoundMrPolarityb.p. / °C
propene42non-polar−48
ethanal44polar20
CH₃Cl50.5more polar−24
CH₃Br94.9less polar4
  • Similar Mr: polar ethanal has pd–pd as well as id–id → higher b.p.
  • Very different Mr: CH₃Br has many more e⁻ → stronger id–id outweighs the pd–pd of CH₃Cl
5

Intermolecular Forces

5.3Hydrogen bonding (H bond)

DefinitionHydrogen bond: weak electrostatic forces of attraction between the protonic hydrogen of one molecule and a lone pair on a highly electronegative atom of another molecule.
  1. At least one H atom directly bonded to F, O or N
  2. The neighbouring molecule has at least one lone pair on F, O or N

Why only F, O and N? They are highly electronegative, so H carries a large δ+, and their lone pair sits in a small 2p orbital with high electron density.

5

Intermolecular Forces

5.3Strength of a hydrogen bond

The more polar the H–X bond, the stronger the hydrogen bond. Electronegativity F > O > N → strength of one H bond: HF > H₂O > NH₃

5.3Extent of hydrogen bonding

AnalogyEach protonic H is a hand, each lone pair is a handle. One H bond = one hand holding one handle, so the number of H bonds per molecule is the smaller of the two numbers.

Moleculehands (H)handles (lone pairs)H bonds / molecule
H₂O222
HF131
NH₃311
6

Physical Properties of Covalent Substances

Boiling points of hydrides / °C

H₂O, HF and NH₃ boil far higher than the trend in id–id predicts, because of hydrogen bonding.

Worked exampleExplain why the boiling points are H₂O (100 °C) > HF (20 °C) > NH₃ (−33 °C), using both the strength and the extent of hydrogen bonding.

  1. All three have hydrogen bonds between molecules, b.p. depends on both their strength and their extent
  2. Strength: H–F is the most polar bond, so one H bond between HF molecules is the strongest, then H₂O, then NH₃
  3. Extent: each H₂O can form 2 H bonds (2 H atoms, 2 lone pairs), but HF and NH₃ form only 1 on average
  4. H₂O: more energy is required to overcome the more extensive H bonds, which outweighs their slightly lower strength → highest b.p.
  5. HF vs NH₃: same extent, but the H bonds between HF molecules are stronger → b.p. HF > NH₃
6

Physical Properties of Covalent Substances

Diamond
  • Each C covalently bonded to 4 others, tetrahedrally
  • Very high m.p.: a large amount of energy is needed to overcome the strong and extensive covalent bonds, hard: atoms are held rigidly
  • Non-conductor: all 4 valence e⁻ of each C are used in bonding → no mobile electrons
Graphite
  1. Each C bonded to 3 others in a layer (hexagons)
  2. The 4th valence e⁻ of each C is delocalised within each layer → conducts parallel to the layers
  3. Soft: weak id–id between layers let them slide
Notem.p. diamond (3350 °C) > Si (1410 °C): C uses smaller, less diffused 2sp³ orbitals → more effective overlap → stronger C–C bonds. Both diamond and graphite are insoluble in all solvents.
6

Physical Properties of Covalent Substances

6.3Density of ice

  1. Ice adopts an open, crystalline structure with hexagonal holes
  2. Each H₂O forms H bonds with 4 other H₂O molecules, each O is surrounded tetrahedrally by 4 H atoms: 2 covalent bonds, 2 H bonds
  3. The regular arrangement spaces molecules more widely than in the liquid → water expands on freezing → ice is less dense than water
6

Physical Properties of Covalent Substances

6.3Intramolecular H bonds

2-nitrophenol (b.p. 216 °C) < 4-nitrophenol (279 °C)

  1. The –OH and –NO₂ groups are in close proximity and correctly oriented for an intramolecular H bond
  2. → the H atom of –OH is less available for intermolecular H bonds
  3. Boiling overcomes intermolecular H bonds → less energy needed → lower b.p.
6

Physical Properties of Covalent Substances

Other effects of hydrogen bonding

  • Ethanol, NH₃, HF and ethanoic acid are miscible with water: they form H bonds with water molecules.
  • Ethanoic acid in benzene forms H-bonded dimers (apparent Mr 120, not 60).

Quick checkWhich has the highest b.p.?

ACH₄
BNH₃
CH₂O
DHF
NoteC: water has the most extensive hydrogen bonding, 2 per molecule.
7

Structure and Physical Properties

Structurem.p. / b.p.Electrical conductivitySolubilityHardness
Giant metallichigh: strong metallic bondsgood in all states: delocalised e⁻insoluble (some react with water)malleable, ductile
Giant ionichigh: strong ionic bondsonly molten / aqueous: mobile ionssoluble in polar solvents (ion–dipole)hard, brittle
Giant molecularvery high: strong, extensive covalent bondsnon-conductor (graphite: along layers)insoluble in all solventsdiamond hard, graphite soft
Simple molecularlow: weak IMF between moleculesnon-conductor: discrete, uncharged moleculeslike dissolves likesoft
7

Structure and Physical Properties

Answer structureMelting point State each structure → more energy is needed to overcome the stronger (type of attraction) between the (particles) of ZZ than the weaker … of YY. Same structure? Explain the factor that makes one attraction stronger.
Answer structureSolubility Energy released forming solute–solvent interactions is / is not able to compensate for the energy needed to overcome the solute–solute and solvent–solvent interactions.

Your turnExplain why SiO₂ melts at 1710 °C but CO₂ is a gas at room temperature.

SiO₂ has a giant molecular structure, CO₂ has a simple molecular structure[1]
Hence, more energy is needed to overcome the stronger, extensive covalent bonds between Si and O atoms in SiO₂ than the weaker instantaneous dipole–induced dipole interactions between CO₂ molecules.[1]

Exit ticket

1Why can metals be hammered into shape?

Metallic bonds are non-directional: layers of cations slide without overcoming the attraction to the sea of e⁻.[1]

2Shape and bond angle of H₂O?

2 bond pairs and 2 lone pairs: bent, 104.5°[1]

3Why is CO₂ non-polar although C=O is polar?

It is linear, so the two bond dipoles cancel: no overall dipole moment.[1]

4Why does ice float on water?

The hydrogen bonds in ice hold the molecules in an open structure, further apart than in the liquid, so ice is less dense.[1]