Atomic Structure

Singapore Junior Chemistry Olympiad

By the end of this chapter, you can answer

1

What makes an atom of one element different from an atom of another?

2

How many protons, neutrons and electrons are in an ion such as Ca²⁺ or S²⁻?

3

A beam of protons, neutrons and electrons passes between two charged plates. Which way does each bend, and which bends most?

4

Why does potassium put its 19th electron into 4s and not 3d, and why does Fe²⁺ lose 4s before 3d?

5

Why is the second electron of sodium about nine times harder to remove than the first?

6

Why is the first ionisation energy of aluminium lower than that of magnesium?

Recall: Chapter 1

1What is the smallest particle of an element called?

An atom. Atoms can be joined together into molecules.

2What does the formula H₂O tell you about a water molecule?

It has two hydrogen atoms and one oxygen atom.

3Can an element be broken down into simpler substances?

No, not by chemical methods. In this chapter we look inside the atom itself.
1

The Atom

ParticleRelative chargeRelative mass
pproton+11
nneutron01
eelectron−11/1836
  • Protons and neutrons reside together in the nucleus, which holds almost all the mass and all the positive charge.
  • Electrons move in regions of space around the nucleus and are attracted electrostatically by the protons.
  • An atom is neutral, so protons = electrons.
NoteIf the nucleus were a 1 cm marble, the whole atom would be about 1 km across. The atom is mostly empty space.
1

Proton Number, Nucleon Number and Ions

3517Cl
17 p,  35 − 17 = 18 n,  17 e⁻

Nucleon number (mass number): total number of protons and neutrons in the nucleus of an atom.

Proton number (atomic number): number of protons in the nucleus. It determines the identity of the element.

Neutrons = nucleon number − proton number.

Atomno. of p = no. of e⁻
Cationloses e⁻: p > e⁻
Aniongains e⁻: e⁻ > p
1

Proton Number, Nucleon Number and Ions

Your turnComplete the table. The first row is done for you.

SpeciesProtonsNeutronsElectrons
23Na111211
23Na⁺111210
32S²⁻161618
65Zn²⁺303528
Exam tipCharge changes only the electrons: no. of e⁻ = proton number − charge. Protons and neutrons never change in chemical reactions. Particles with the same number of electrons, such as Na⁺, Ne and F⁻, are isoelectronic.
1

Isotopes

DefinitionIsotopes are atoms of the same element with the same number of protons but different numbers of neutrons.
  • Same electronic configuration → same chemical properties: chemical reactions involve electrons, not the nucleus.
  • Different masses → different physical properties, for example density and rate of diffusion.

Name an isotope with its nucleon number, for example chlorine-35, 35Cl, or 2H.

1

Isotopes

Your turnWhy do isotopes of an element react in the same way but differ in density?

They have the same number of electrons, so they react in the same way.
They have different numbers of neutrons, so their masses differ, and with them the density.

Quick checkWhich pair are isotopes?

A¹²₆C and ¹⁴₇N
B¹²₆C and ¹⁴₆C
C²³₁₁Na and ²³₁₁Na⁺
D¹⁶₈O and ¹⁶₈O²⁻
NoteB: both have 6 protons and differ in neutrons (6 and 8).
1

Charged Particles in an Electric FieldCore · A Level

PredictWhich way does each beam bend? Which bends the most?
  • Neutrons have no charge: undeflected.
  • Protons are deflected towards the negatively charged plate.
  • Electrons are deflected towards the positively charged plate, to a much larger extent: they are far lighter.
1

Charged Particles in an Electric FieldCore · A Level

Why does the electron bend more?

  • Between the plates, each particle feels a sideways force that depends on its charge. A proton and an electron feel forces of the same size.
  • The same force changes the path of a light particle far more than a heavy one. A proton is 1836 times heavier.
angle of deflection ∝ charge / mass
Particlecharge / massDeflection
proton+1 / 1 = +1small, towards −
neutron0 / 1 = 0none
electron−1 / (1/1836) = −1836large, towards +
1

Charged Particles in an Electric FieldCore · A Level

Worked exampleA beam of 241Am+ ions is deflected by +2°. Under the same conditions, find the angle of deflection of 32S− ions.

Step 1Write the relationship with a constant:  θ = k × chargemass

Step 2Use the ion you know to find k:  Am⁺:  +2 = k × +1241 → k = 482

Step 3Apply k to the new ion:  S⁻:  θ = 482 × −132 = −15.1°

NoteThe negative sign means S⁻ bends the opposite way to Am⁺. It bends more because its charge / mass is larger in size: 1/32 against 1/241.
1

Charged Particles in an Electric FieldCore · A Level

Your turnA beam of 1H⁺ ions is deflected +4°. What is the deflection of 2H⁺ ions under the same conditions?

The charge is unchanged and the mass doubles, so the angle halves to +2°.

Quick checkWhich beam is deflected most in the same electric field?

Aneutrons
Bprotons
Celectrons
Dalpha particles
NoteC: electrons have the largest charge-to-mass ratio, because their mass is so small.
2

Electrons in Atoms

Electrons fill shells from the inside out. For the first 20 elements, shell 1 holds 2, and shells 2 and 3 hold 8 each. Sodium is 2.8.1.

  • The outer shell is the valence shell. A full valence shell is stable, which is why the noble gases are unreactive.
  • Period number = number of occupied shells. Group 1 and 2: group number = valence electrons. Groups 13 to 18: group number − 10.
  • This 2.8.8 pattern breaks down after calcium. The finer picture of shells, subshells and orbitals explains why.
2

Electrons in Atoms

The Periodic Table lists the elements in order of proton number. Its rows are periods and its columns are groups, numbered 1 to 18. Groups 3 to 12 begin only in Period 4.

Sodium (11) is in Period 3, Group 1: three shells, one valence electron (2.8.1).

2

Shells, Subshells and OrbitalsCore · A Level

Principal quantum shells, subshells and orbitals

Atomthe hotel
→
Shellsn = 1, 2, 3 …floors
→
Subshellss, p, d, ftypes of room
→
Orbitalss: 1, p: 3, d: 5rooms
→
2 e⁻ maxper orbital2 guests per room
  • A larger n gives a larger, more diffused orbital, further from the nucleus, and hence a higher energy: higher floors cost more.
  • Shell n has n types of room: shell 3 has 3s, 3p and 3d.
2

Shells, Subshells and OrbitalsCore · A Level

AnalogyGuests (electrons) check in one at a time. Every guest wants to pay as little as possible.

  • Rooms on lower floors are cheaper, and within a floor s < p < d.
  • Guests take the cheapest room available.
  • Nobody wants to share with a stranger, but if the next empty room costs much more, sharing is the better deal.
  • Rooms of the same price: each guest takes an empty one before anyone shares.

These are the three filling rules in 2.3.3.

2

Shells, Subshells and OrbitalsCore · A Level

What is an orbital?

We cannot know exactly where an electron is. Instead, imagine taking a snapshot of its position again and again, and marking a dot each time.

The dots build up a cloud: dense near the nucleus, thinning out further away.

DefinitionOrbital: the region of space where there is a high probability (95%) of finding an electron. Each orbital can accommodate 2 electrons.
2

Shells, Subshells and OrbitalsCore · A Level

nSubshellsOrbitals in eachTotal orbitals (n²)Max e⁻ (2n²)
11s112
22s, 2p1, 348
33s, 3p, 3d1, 3, 5918
44s, 4p, 4d, (4f)1, 3, 5, (7)1632
PredictHow many orbitals, and how many electrons, can shell 3 hold?

4f is not needed in this course. The 3 p orbitals are px, py, pz, the 5 d orbitals are dxy, dxz, dyz, dx²−y², dz².

2

Shells, Subshells and OrbitalsCore · A Level

Relative energies of the orbitals

  • Energy rises with n: 1s < 2s < 3s < 4s.
  • Within a shell: s < p < d < f. Orbitals of the same subshell have the same energy: they are degenerate.
  • The levels get closer together as n increases, until they overlap. The first overlap: 4s is lower in energy than 3d, so 4s fills first.
2

Shells, Subshells and OrbitalsCore · A Level

Shapes of orbitals

  • s: spherical. p: dumb-bell, one along each axis.
  • d: dx²−y² and dz² point along the axes, dxy, dxz and dyz point between the axes.
2

Electronic ConfigurationCore · A Level

Two ways to represent it

Electrons-in-boxes

Each orbital is a box, each electron is a half arrow. Two electrons in one box point in opposite directions (opposite spins).

Argon. Label boxes with the subshell only (2p, not 2p⁶).

2

Electronic ConfigurationCore · A Level

Rules for filling orbitals

Aufbau principle
Electrons fill the orbitals of lowest energy first. After 3p, 4s is filled before 3d.
Pauli exclusion principle
An orbital holds a maximum of two electrons, of opposite spins.
Hund's rule
Orbitals of a subshell are filled singly first, with parallel spins, before pairing. This gives less inter-electronic repulsion.
2

Electronic ConfigurationCore · A Level

Order of filling

Using the order

  • Follow the arrows: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p.
  • The block of an element is the subshell filled last: s-block, d-block, p-block.
  • The period number is the n of the valence shell. For example Na is Period 3 and the s block, so it ends 3s¹. P is the 3rd element of the p block in Period 3, so it ends 3p³.
  • A noble gas shorthand shows the inner electrons as the previous noble gas: Br is [Ar] 3d¹⁰ 4s² 4p⁵.
2

Electronic ConfigurationCore · A Level

Worked exampleWrite the full electronic configuration of iron, Fe (26 electrons).

Step 1Fill in energy order: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² (20 e⁻ so far)

Step 2The last 6 go into 3d: 3d⁶ (26 e⁻)

Step 3Write in order of increasing n: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶ 4s²

Exam tipWrite the full configuration with 3d before 4s, and check that the superscripts add up to the number of electrons.

Your turnWrite the full electronic configurations of:

(a) K (19)

1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹

(b) Mn (25)

1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s²

(c) Br (35)

1s² 2s² 2p⁶ 3s² 3p⁶ 3d10 4s² 4p⁵
2

Chromium and CopperCore · A Level

Anomalies: Cr and Cu

PredictUsing the Aufbau principle, what do you expect for Cr (24 e⁻) and Cu (29 e⁻)?

Cr expected [Ar] 3d⁴ 4s², actual [Ar] 3d⁵ 4s¹

Cu expected [Ar] 3d⁹ 4s², actual [Ar] 3d10 4s¹

A half-filled (d⁵) or fully-filled (d10) 3d subshell is more stable.

3d and 4s are very close in energy, so moving one electron costs little, and the more stable d⁵ or d10 arrangement wins.

2

Configurations of IonsCore · A Level

Configurations of ions

Fe fills 4s before 3d.

PredictSo does Fe²⁺ lose its last-in electrons, two of the 3d?

Cation: electrons are removed from the outermost shell of the ground state configuration: 4s before 3d. Once 3d holds electrons, 4s (n = 4) is the outermost shell.

Anion: electrons are added to the empty or partially-filled valence orbitals, for example S²⁻: 1s² 2s² 2p⁶ 3s² 3p⁶.

2

Configurations of IonsCore · A Level

Quick checkWhat is the electronic configuration of Cu²⁺?

A[Ar] 3d⁹
B[Ar] 3d⁸ 4s¹
C[Ar] 3d⁷ 4s²
D[Ar] 3d10
NoteA: Cu is [Ar] 3d10 4s¹ (an anomaly). Remove the 4s electron first, then one 3d electron: [Ar] 3d⁹. Option C forgets the anomaly and removes 3d before 4s.
3

Ionisation EnergyCore · A Level

DefinitionFirst ionisation energy: the energy required to remove 1 mole of electrons from 1 mole of gaseous atoms.
X(g) → X⁺(g) + e⁻1st IE of X X⁺(g) → X²⁺(g) + e⁻2nd IE of X
  • All IEs are endothermic: energy must be put in to pull an electron away from the attraction of the nucleus.
  • Gaseous atoms are far apart, so the energy measured is only for removing the electron. (g) is the state symbol for gas.
  • A mole is a fixed number of particles, 6.02 × 10²³. kJ mol⁻¹ means kilojoules for one mole of atoms.
3

Ionisation EnergyCore · A Level

Shielding and effective nuclear charge

The outer electron is pulled by every proton, but the inner electrons sit between it and the nucleus and repel it, cancelling part of that pull: shielding.

Effective nuclear charge, Zeff = Z − shielding: the pull an outer electron actually feels.

AnalogyStanding in the back row of a concert: the crowd in front (inner electrons) blocks most of the stage, however big the stage (nucleus) is.

Electrons in the same shell shield each other very little.

3

Ionisation EnergyCore · A Level

First IE of elements 1 to 20 / kJ mol⁻¹

DescribeDescribe the patterns you see.
  • Peaks at the noble gases, a sharp drop to each Group 1 metal.
  • Generally increases across a period.
  • Decreases down a group: He > Ne > Ar.
  • Two small dips in each period: B, Al and O, S.
3

Ionisation EnergyCore · A Level

Across periods 2 and 3, 1st IE generally ↑

  1. Nuclear charge ↑, while there is a negligible ↑ in inner shell shielding effect, as e⁻ are added to the same shell
  2. → effective nuclear charge ↑, atomic radius ↓
  3. → valence e⁻ more strongly attracted by the nucleus → more energy required to remove them
3

Ionisation EnergyCore · A Level

Down a group, 1st IE ↓

  1. Atomic radius ↑
  2. No. of principal quantum shells ↑ → shielding effect ↑, which largely cancels out the ↑ in nuclear charge
  3. → valence e⁻ less attracted by the nucleus → less energy required to remove them
Exam tipAlways state the effect on attraction and then on the energy required: these are the mark points.
3

Ionisation EnergyCore · A Level

Dips: Be → B (also Mg → Al)

Be1s2 2s2B1s2 2s2 2p1

PredictThe 2p electron is higher in energy. Does that make it harder or easier to remove?

AnalogyThink of a deep well. Removing an electron means lifting it to the top (where it is free). A ball resting on a higher ledge needs a shorter lift.

The 2p electron removed from B is higher in energy than the 2s electron removed from Be.
Hence, less energy is required to remove it, and the first ionisation energy of B is lower than that of Be.
3

Ionisation EnergyCore · A Level

Dips: N → O (also P → S)

AnalogyBack to the hotel: O's 8th guest had to share a 2p room with a stranger. Two guests in one room push each other, so one of them is easier to move out.

There is Coulombic repulsion between the paired 2p electrons in O, so it is easier to remove one of them than an unpaired 2p electron from N.
Hence, less energy is required, and the first ionisation energy of O is lower than that of N.
3

Successive Ionisation EnergiesCore · A Level

  • Successive ionisation energies always increase: the same protons hold fewer and fewer electrons.
  • Gradual increase: electrons removed from the same subshell. A small jump: the next electron is from a lower energy subshell of the same shell.
  • Big jump: the next electron comes from an inner shell, nearer the nucleus and less shielded. The number removed before the jump is the group's valence electrons.
3

Successive Ionisation EnergiesCore · A Level

Worked exampleThe successive IEs of element X are shown below. Predict the Group of X.

IE / kJ mol⁻¹8701800300036005800700013000
  1. Successive IEs ↑ as each e⁻ is removed from an ion of increasing positive charge
  2. 1st to 6th IE ↑ gradually: removal of the outermost e⁻ only
  3. Sharp ↑ from 6th to 7th IE: 7th e⁻ removed from an inner principal quantum shell, nearer to the nucleus, with less shielding
  4. ∴ 6 e⁻ in the outermost shell → X is in Group 16
3

Successive Ionisation EnergiesCore · A Level

Your turnThe first seven ionisation energies of J in kJ mol⁻¹ are 1020, 1950, 2730, 4580, 6020, 12 300 and 15 400. Which group is J in?

The big jump is between the 5th and 6th, so J has 5 valence electrons and is in Group 15.

ChallengeExplain why the second ionisation energy of sodium is much greater than its first.

The first electron comes from the outer 3s subshell. The second must be removed from the inner 2p subshell of Na⁺, which is closer to the nucleus and more strongly attracted.

Exit ticket

Quick checkHow many neutrons are in ⁶⁵₃₀Zn²⁺?

A28
B30
C35
D37
NoteC: neutrons = 65 − 30 = 35. The charge changes the electrons, not the neutrons.

Quick checkWhich element has a first ionisation energy lower than that of the element before it in the period?

AMg
BAl
CSi
DP
NoteB: Al loses a 3p electron, which is higher in energy than Mg's 3s electron.